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24x^2=1000x
We move all terms to the left:
24x^2-(1000x)=0
a = 24; b = -1000; c = 0;
Δ = b2-4ac
Δ = -10002-4·24·0
Δ = 1000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1000000}=1000$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1000)-1000}{2*24}=\frac{0}{48} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1000)+1000}{2*24}=\frac{2000}{48} =41+2/3 $
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